GCSE Maths – June 2019 Edexcel 1MA1/1F Paper 1 (Non-Calculator)
Write 180 minutes in hours.
There are 60 minutes in 1 hour.
$180\div60=3$ hours (B1)
3 hours
Write 0.73 as a percentage.
Multiply by 100 and add ‘%’.
$0.73\times100=73\%$ (B1)
73%
Work out $10\times(3+5)$.
Brackets first: $(3+5)=8$.
Then $10\times8=80$ (B1)
80
Write down a prime number between 20 and 30.
Primes in that range are 23 and 29. (B1)
23 (or 29)
Find the number halfway between 7 and 15.
Add and divide by 2: $(7+15)\div2=22\div2=11$ (B1)
11
Travel cost £150 per person. Hotel cost £50 per day per person. Spending money £250 each. Four people stay 7 days. Work out the total cost.
Hotel per person: $7\times50=£350$ (M1)
Other costs: £150 + £250 = £400 (M1)
Total per person = £350 + £400 = £750 (M1)
For 4 people: $4\times750=£3000$ (A1)
£3000
The bar chart shows how many flowers of each colour there are in a bunch.
Total flowers = 30.
(a) How many blue flowers are in the bunch?
(b) Write down the mode colour of the flowers.
(a) Red = 8, White = 10, Yellow = 5 → total 23 (M1)
Blue = 30 − 23 = 7 (A1)
7 blue flowers
(b) Highest bar = white (B1)
White
Order $\frac13,\;\frac34,\;\frac14,\;\frac7{12},\;\frac12$ from smallest to largest.
Convert to denominator 12 for comparison: $\frac14=\frac3{12}$, $\frac13=\frac4{12}$, $\frac12=\frac6{12}$, $\frac7{12}$, $\frac34=\frac9{12}$. (M1)
Smallest to largest: $\frac14,\;\frac13,\;\frac12,\;\frac7{12},\;\frac34$ (A1)
$\frac14,\;\frac13,\;\frac12,\;\frac7{12},\;\frac34$
Ruth leaves home at 9 a.m. and walks to the library. She walks at a speed of 4 miles per hour and arrives at 10:30 a.m.
(a) Work out how far she walks.
She stays at the library for 50 minutes and then walks home at a speed of 3 miles per hour.
(b) What time does Ruth get home?
(a) Time walking to library = 1.5 hours.
Distance = speed × time = $4 \times 1.5 = 6$ miles (M1)(A1)
6 miles
(b) She leaves library at 10:30 + 50 minutes = 11:20 a.m. (M1)
Time to walk 6 miles home at 3 mph: $6 \div 3 = 2$ hours.
Arrives home at 11:20 + 2 hours = 1:20 p.m. (A1)
(a) $t + t + t = 12$
(b) $x – 2 = 6$
(c) $6w + 2 = 20$
Solve each equation.
(a) Combine terms: $3t = 12 \Rightarrow t = 4$ (B1)
4
(b) Add 2 to both sides: $x = 8$ (B1)
8
(c) Subtract 2: $6w = 18 \Rightarrow w = 3$ (M1)(A1)
3
Work out $74 \times 58$.
Break into parts: $(70 + 4)(50 + 8)$
$= 70 \times 50 + 70 \times 8 + 4 \times 50 + 4 \times 8$ (M1)
$= 3500 + 560 + 200 + 32 = 4292$ (A1)
4292
(a) AB is perpendicular to BC. Angle ABC = 90°. Two other angles of 25° are marked on the diagram. Find the value of x.
(b) Lines RS and TU are parallel. PQ is a straight line crossing them. One angle is 125°.
(i) Write down another angle equal to 125° and give a reason.
(ii) Explain why $a + b + c = 235$.
(a) Right angle at B = 90°. The other two angles are 25° each, so $x = 90 – 25 – 25 = 40°$ (M1)(A1)
40°
(b)(i) Angle b (or d) also = 125° because they are vertically opposite (or corresponding) angles. (B1)(C1)
125°
(b)(ii) Angles around a point add up to 360°.
$360 – 125 = 235$, so $a + b + c = 235°$ (C1)
235°
A length is x cm. Write an expression for this length in millimetres.
1 cm = 10 mm, so $x$ cm = $10x$ mm (B1)
$10x$
(a) Work out $\frac15$ of 70.
(b) Fiona says “$48 \div \frac12 = 24$ because there are 2 halves in 1.” Explain what is wrong.
(a) $\frac15 \times 70 = 14$ (B1)
14
(b) Dividing by $\frac12$ doubles the number, not halves it. $48 \div \frac12 = 96$, not 24. (C1)
She divided instead of multiplying.
(a) Write the value of $\sqrt{64}$.
(b) Work out $5^3$.
(a) $\sqrt{64} = 8$ (B1)
8
(b) $5^3 = 5\times5\times5 = 125$ (B1)
125
